Acknowledgment for Frame 1. Acknowledgment for Frame 2. Acknowledgment for Frame 3. Sent Frame 4. Sent Frame 5. Sent Frame 6. Frame 4 Not Received. Retransmitting Window. Acknowledgment for Frame 4. Acknowledgment for Frame 5. Acknowledgment for Frame 6. Sent Frame 7. Sent Frame 8. The size of the sender's window is 4. Step 1: As the window size is 4, so four packets are transferred at a time, i.
Step 2: Once the transfer of window size is completed, the sender receives the acknowledgment of the first frame, i. As the acknowledgment receives, the sender sends the next packet, i. In this case, the window slides having four packets, i. Step 3: Now, the sender receives the acknowledgment of packet 2.
After receiving the acknowledgment for packet 2, the sender sends the next packet, i. As mentioned in the question that every 6 th is being lost, so this 6 th packet is lost, but the sender does not know that the 6 th packet has been lost. Step 4: The sender receives the acknowledgment for the packet no 3. After receiving the acknowledgment of 3 rd packet, the sender sends the next packet, i.
The window will slide having four packets, i. Step 5: When the packet 7 has been sent, then the sender receives the acknowledgment for the packet no 4. When the sender has received the acknowledgment, then the sender sends the next packet, i. Step 6: When the packet 8 is sent, then the sender receives the acknowledgment of packet 5. On receiving the acknowledgment of packet 5, the sender sends the next packet, i. Step 7: The current window is holding four packets, i.
As we know, the 6 th packet has been lost, so the sender receives the negative acknowledgment NAK 6. As we know that every 6 th packet is being lost, so the counter will be restarted from 1. So, the counter values 1, 2, 3 are given to the 7 th packet, 8 th packet, 9 th packet respectively.
It will resend 6, 7, 8, 9. The counter values of 6, 7, 8, 9 are 4, 5, 6, 1, respectively. In this case, the 8 th packet is lost as it has a 6-counter value, so the counter variable will again be restarted from 1.
Step 9: After the retransmission, the sender receives the acknowledgment of packet 6. On receiving the acknowledgment of packet 6, the sender sends the 10 th packet. Now, the current window is holding four packets, i. Step When the 10 th packet is sent, the sender receives the acknowledgment of packet 7.
Now the current window is holding three packets, 8, 9 and The counter values of 8, 9, 10 are 6, 1, 2. Step As the 8 th packet has 6 counter value which means that 8 th packet has been lost, and the sender receives NAK 8. Step Since the sender has received the negative acknowledgment for the 8 th packet, it resends all the packets of the current window, i.
Step The counter values of 8, 9, 10 are 3, 4, 5, respectively, so their acknowledgments have been received successfully. JavaTpoint offers too many high quality services. Mail us on [email protected] , to get more information about given services.
Espn roland garros tv schedule. Selective Repeat: Sender transmits only that frame which is erroneous or is lost. Go back n: Sender transmits all frames present in the window that occurs after the error bit including error bit also.
Output Enter window size: 3 Enter number of frames to transmit: 5 Enter 5 frames: 12 5 89 4 6 With sliding window protocol the frames will be sent in the following manner assuming no corruption of frames After sending 3 frames at each stage sender waits for acknowledgement sent by the receiver 12 5 89 Acknowledgement of above frames sent is received by sender 4 6 Acknowledgement of above frames sent is received by sender Sliding Window Protocol Program in C Below is the simulation of sliding window protocol in C.
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